21y+5y^2=20

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Solution for 21y+5y^2=20 equation:


Simplifying
21y + 5y2 = 20

Solving
21y + 5y2 = 20

Solving for variable 'y'.

Reorder the terms:
-20 + 21y + 5y2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + 21y + 5y2 = 0

Factor a trinomial.
(-5 + -1y)(4 + -5y) = 0

Subproblem 1

Set the factor '(-5 + -1y)' equal to zero and attempt to solve: Simplifying -5 + -1y = 0 Solving -5 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1y = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1y = 0 + 5 -1y = 0 + 5 Combine like terms: 0 + 5 = 5 -1y = 5 Divide each side by '-1'. y = -5 Simplifying y = -5

Subproblem 2

Set the factor '(4 + -5y)' equal to zero and attempt to solve: Simplifying 4 + -5y = 0 Solving 4 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5y = 0 + -4 -5y = 0 + -4 Combine like terms: 0 + -4 = -4 -5y = -4 Divide each side by '-5'. y = 0.8 Simplifying y = 0.8

Solution

y = {-5, 0.8}

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